In a small town the population is
p0 = 1000 at the beginning of a year. The population regularly increases by
2 percent per year and moreover
50 new inhabitants per year come to live in the town. How many years does the town need to see its population greater or equal to
p = 1200 inhabitants?
More generally given parameters:
p0, percent, aug (inhabitants coming or leaving each year), p (population to surpass)
nb_year should return
n number of entire years needed to get a population greater or equal to
aug is an integer, percent a positive or null floating number, p0 and p are positive integers (> 0)
Don’t forget to convert the per cent parameter as a percentage in the body of your function: if the parameter percent is 2 you have to convert it to 0.02.
procedure nbYear(p0, percent, aug, p) 1. years = 0 2. for years until p0 >= p A. p0 += p0 * (percent / 100) + aug 3. return years
Depending on the language, the implementation using for loop or recursive call might make difference in the performance of the algorithm.